Question

Identify a and b in the binomial expression (2x3 + 3y2)7.​

Answer 1

$\text{Hey there!}$

$\text{Distribute the value of 7 in each of your terms}$

$\text{(2x}^3+\text{3y}^2)(7)$

$\text{2x}^3\times7=\text{14x}^3$

$\text{3y}^2\times7=\text{21y}^2$

$\text{We cannot combine like terms because they AREN'T any in this equation}$

$\boxed{\boxed{\bf{Answer:14x^3+21y^2}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~$\frak{LoveYourselfFirst:)}$

Answer 2

Answer:

$a=2x^3$ and $b=3y^2$

Step-by-step explanation:

The given binomial expression is:  $(2x^3+3y^2)^7$

A standard binomial expression is like  $(a+b)^n$

Comparing the given expression with the standard binomial expression.....

$(a\ \ +\ \ b)^n \Longleftrightarrow (2x^3\ +\ 3y^2)^7\\ \\ So,\ \ a=2x^3\\ \\ and\ \ b=3y^2$