Does anyone know how to solve this?
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The range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
<h3>What is the range of the function?</h3>Range of a function is the set of all the possible output values which are valid for that function.
The trigonometry function given in the problem is,
The above function can be written as,
The above function is the arc of sine function. The domain of arc of sine ranges from -1 to 1.
This is the domain of the inverse of sine function. In the attached image below, the graph of inverse sine function is plotted. The range of this function is,
Thus, the range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
Learn more about the range of the function here;
