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When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
4
Step-by-step explanation:
Answer:
70
Step-by-step explanation:
Its 70 because you see the degree is 110 so try to subtract 180 degrees by 110 and you get 70 so it's the answer
3.25 you just subtract 3.75 from 7
Hope this helps!
