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stepladder [879]
3 years ago
13

A current i travels counterclockwise through a closed copper wire loop which has the shape of a rectangle with sides 'a' and 'b'

. what is the magnitude of the magnetic field at the center, c, of the rectangle? express your answer in terms of a, b, i and mu _0. (enter mu_0
Physics
1 answer:
Maru [420]3 years ago
4 0
<span>A current i travels counterclockwise through a closed copper wire loop which has the shape of a rectangle with sides</span>
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*Look at attachment for photo of object**
prohojiy [21]

A. The magnitude of the spring force (in N) acting upon the object is 15.9 N

B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²

C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).

<h3>A. How to determine the force </h3>
  • Extension (e) = 0.150 m
  • Spring constant (K) = 106 N/m
  • Force (F) = ?

F = Ke

F = 106 × 0.15

F = 15.9 N

<h3>B. How to determine the acceleration</h3>
  • Mass (m) = 0.52 Kg
  • Force (F) = 15. 9 N
  • Acceleration (a) =?

F = ma

Divide both sides by m

a = F / m

a = 15.9 / 0.52

a = 30.58 m/s²

<h3>C. How to determine the direction of the acceleration vector</h3>

Considering the diagram, we can see that the spring was pulled away from the equilibrium point.

Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.

Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

3 0
2 years ago
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? S
amm1812

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

v is image distance

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

If h' is the height of the image. Magnification is given by :

m=\dfrac{h'}{h}=\dfrac{v}{u}

h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm

So, the height of the image of the candle is 20 cm.

3 0
3 years ago
What is matter? explain and give example
kotykmax [81]
Matter is generally any physical substance, and it's all around us... a form of matter would be liquid, and water is a liquid.
4 0
3 years ago
What is formed from at least two types of chemically combined atoms?
SashulF [63]
A compound. For example, hydrogen and oxygen atoms form water.
7 0
3 years ago
List two functions of blood plasma
dexar [7]

Answer:

•Helps to maintain va proper pH in the body which supports cell function.

•Carries electrolytes such as sodium and potassium to our muscles.

8 0
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