Question

Charges q and Q are placed on the x axis at x = 0 and x = 2.0m, respectively. If q= -40 pC and Q =+30 pC, determine the net flux through a spherical surface (radius = 1.0 m) centered on the origin.

Answer 1

Answer:

Explanation:

q = - 40 pC at x = 0 m

Q = 30 pC at x = 2 m

flux at r = 1 m

As the enclosed charge is q. So, by the Gauss theorem,

$\phi =\frac{q}{\epsilon _{0}}$

$\phi =\frac{40\times 10^{-12}}{8.854\times 10^{-12}}$

Ф = 4.52 Nm²/C

Answer 2

Answer:

Explanation:

Charge q  will remain inside the given sphere and charge Q will remain outside it.

So charge inside sphere = - 40 x 10⁻¹² C

According to Gauss's law

Net flux over the spherical closed surface

= charge inside the surface / ε₀

= - 40 x 10⁻¹²  / 8.85  x 10⁻¹²

= - 4.52 Weber.

- ve sign indicates , flux is oriented towards the center.