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Anon25 [30]
3 years ago
10

Write a few sentences about different ways to show subtraction for a problem 32-15.

Mathematics
2 answers:
Serhud [2]3 years ago
8 0

You have 32 tiles, you use 15 tiles, how many tiles are left?

You just went shopping with $32, you spent $15, how much money do you have left?

Your friend has 32 cards, he loses 15, how many cards does he have left?

otez555 [7]3 years ago
8 0
You can estimate by doing 30-10 then 5-2. You can do the obvious one 32-15
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F(x)= sqrt of 5x+7 and g(x)= the sqrt of 5x-7
ki77a [65]
F(x) = √(5x + 7)

g(x) = √(5x - 7)

(f + g)(x) = f(x) + g(x)

(f + g)(x) = √(5x + 7) + √(5x - 7)

Answer: C)
4 0
3 years ago
Need help on these. Don't answer if you don't know. I'm looking at YOU, bmdaniel1
andre [41]

Answer:

use m a t h w a y

really easy to use

works for all algebraic equations

Step-by-step explanation:

7 0
3 years ago
How to write the number 63 in four different ways
shtirl [24]
63/1
sixty-three
63^1
63
7 0
3 years ago
Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}
Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

(d)

To begin with A,B  \subset A \cup B, therefore

g(A) \cup g(b) \subset g(A\cup B)

7 0
3 years ago
Pls answer this question for ill give brainliest
notka56 [123]

Answer:

BE=15

Step-by-step explanation:

Since E is the center, BE=2x+1

And AC is 6x-12 with E being a midpoint.

Since AC is 2 segments and BE is only 1 then you multiply 2x+1 by 2 so that

you can find x. You multiply 2x+12 by 2 because E is the midpoint so that means ED is the same value as BE

6x-12=4x+2

BD=AC

6x-4x-12=2

2x=2+12

2x=14

x=7

BE= 2x+1

2(7)=14+1=15

7 0
2 years ago
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