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sdas [7]
2 years ago
7

On Martin's first stroke, his golf ball traveled 4 5 5 4 ​ start fraction, 4, divided by, 5, end fraction of the distance to the

hole. On his second stroke, the ball traveled 79 7979 meters and went into the hole.
Mathematics
1 answer:
faltersainse [42]2 years ago
3 0

Answer:

0.395 kilometers

Step-by-step explanation:

Please consider the complete question.

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball went into the hole. Martin was standing 79 meters from the hole as he took his second stroke. How many kilometers from the hole was Martin when he started?

Let x represent the distance between hole and start point.

In 1st stroke ball traveled 4/5 of the distance, so 1/5 of the distance was remaining from 2nd stroke to hole. This means the 1/5 of whole distance between start point and hole is equal to 79 meters.

We can represent this information in an equation as:

\frac{1}{5}x=79

\frac{1}{5}x\cdot 5=79\cdot 5

x=395

Since our distance is in meters, so we will convert 395 meters into kilometers by dividing by 1000.

395\text{ meters}=\frac{395}{1000}\text{ km}=0.395\text{ km}

Therefore, Martin was 0.395 kilometers from the hole, when he started.

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Answer:

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Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = x\times\frac{1}{2} =\frac{x}{2} \ m.

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Now, we put the formula of area to solve:

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<em>Dividing both sides by 3 we get:</em>

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<em>Thus, the height of triangle =  </em>\frac{12}{\sqrt{3}} \ m.<em />

Therefore, the base of triangle is  \frac{8}{\sqrt{3}} \ m and the height of triangle is  \frac{12}{\sqrt{3}} \ m.

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