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sdas [7]
3 years ago
7

On Martin's first stroke, his golf ball traveled 4 5 5 4 ​ start fraction, 4, divided by, 5, end fraction of the distance to the

hole. On his second stroke, the ball traveled 79 7979 meters and went into the hole.
Mathematics
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

0.395 kilometers

Step-by-step explanation:

Please consider the complete question.

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball went into the hole. Martin was standing 79 meters from the hole as he took his second stroke. How many kilometers from the hole was Martin when he started?

Let x represent the distance between hole and start point.

In 1st stroke ball traveled 4/5 of the distance, so 1/5 of the distance was remaining from 2nd stroke to hole. This means the 1/5 of whole distance between start point and hole is equal to 79 meters.

We can represent this information in an equation as:

\frac{1}{5}x=79

\frac{1}{5}x\cdot 5=79\cdot 5

x=395

Since our distance is in meters, so we will convert 395 meters into kilometers by dividing by 1000.

395\text{ meters}=\frac{395}{1000}\text{ km}=0.395\text{ km}

Therefore, Martin was 0.395 kilometers from the hole, when he started.

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7 + 2y = 8x 3x - 2y = 0 Solve the system of equations by substitution. (70/3, 140/9) (7/5, 21/10) no solution coincident
Wittaler [7]
So we have the system of equations:
7+2y=8x equation (1)
3x-2y=0 equation (2)

To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for x in equation (2):
3x-2y=0
3x=2y
x= \frac{2}{3}y equation (3)

Replacing equation (3) in equation (1):
7+2y=8x
7+2y=8( \frac{2}{3} y)
7+2y= \frac{16}{3} y
7= \frac{10}{3} y
y= \frac{7}{ \frac{10}{3} }
y= \frac{21}{10} equation (4)

Replacing equation (4) in equation (3):
x= \frac{2}{3}y
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We can conclude that the solution of our system of equations is <span>(7/5, 21/10)</span>
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