Answer:
BC ≈ 8.6
Step-by-step explanation:
Using Pythagoras' identity in the right triangle , that is
BC² = AB² + AC² = 7.3² + 4.6² = 53.29 + 21.16 = 74.45 ( square root both sides )
BC =
≈ 8.6 ( to 1 dec. place )
(f – g)(x) = 7x - √2 - (x + √2)
(f – g)(x) = 7x - √2 - x - √2
<span>(f – g)(x) = 6x - 2</span>√2
Answer:
Step-by-step explanation:
You have 3 unknowns: a, b, and c. It's our job to find them algebraically. I'm going to start with the point where x = 0 and y = 7. You'll see why in a minute. Filling in the standard form of a quadratic
using (0, 7):
gives you that c = 7. We will use that value now when we write the next 2 equations. Now the point (-2, 19):
and
so
12 = 4a - 2b
Now for the next point (-1, 12):
and
so
5 = a - b
Now we have a system of equations (the 2 bold font equations) that we will solve by elimination:
12 = 4a - 2b
5 = a - b
Multiply the bottom equation by -4 to get a new system:
12 = 4a - 2b
-20 = -4a + 4b
Add those together to get rid of the a terms and end up with
-8 = 2b so
b = -4
Now we can sub in -4 for b to solve for a. I'm using the second bold type equation to do this:
5 = a - (-4) and
5 = a + 4 so
a = 1 and the equation for the quadratic function is

Maybe 200 dollars, 500 dollars and so on
Let car b be travelling at x mph. as they are travelling towards each other their speed of approach is (x + x + 15 ) mph. So we have the equation
speed = distance / time
2x + 15 = 250 / 2
2x = 125 - 15 = 110
x = 55 mph
Car b travels at 55 mph and car a travels at 70 mph Answer