Their are 6 equilateral triangles in a regular hexagon:
The area of one triangle = (x²√3)/4, then:
1st answer: The area of the hexagon base: is 6 TIMES the area of one equilateral triangle [or, needed for 2nd, question, TOT AREA:(6x²√3)/4] = (3x²√3)/2] unit²
2nd answer: :
Volume of pyramid: (base area)(height)/3
Volume of pyramid: (3x²√3).(3x)/3 (because height = 3x, given)
Then Volume of pyramid= 3x³√3 unit³.
3 is the answer for the second question
and 6 for the 1st
Answer:
Required number is 4.
Step-by-step explanation:
Let the required number be a.
Given,
Sum of ten times the integer and seven times it’s square is 152.
= > Ten times of a + seven times of it's square = 152
= > 10( a ) + 7( a )^2 = 152
= > 10a + 7a^2 - 152 = 0
= > 7a^2 + 10a - 152 = 0
= > 7a^2 + ( 38 - 28 )a - 152 = 0
= > 7a^2 + 38a - 28a - 152 = 0
= > a( 7a + 38 ) - 4( 7a + 38 ) = 0
= > ( a - 4 )( 7a + 38 ) = 0
= > a = 4 or - 38 / 7
Hence the required number is 4.
Answer:
<u>So, the way a ratio works is </u><u>"for every 1 of this, we have 4 of this"</u><u> for example. (the ratio I just described would be 1:4.) </u>
<u />
I believe I've seen this question before. If the ratio of dolls to teddy bears is 9:3 then for every 9 dolls you have 3 teddy bears.
So, since we have 240 dolls and a 9:3 ratio to teddy bears, all we have to do is take how many dolls we have (240) and divide it by 3 to see how many teddy bears we have.
So:
240 ÷ 3 = 80
If your ratio is 9:3, then 80 is your answer.
<u>Hope this helps and have a nice day!</u>
<u></u>
<span><span><span>x3</span>+3x5</span>=x5</span><span>3x5+x3=x5</span>Subtract x^5 from both sides.<span>3x5+x3−<span>x5</span>=x5−<span>x5</span></span><span>2x5+x3=0</span>Factor left side of equation.<span><span><span>x3</span>(2x2+1)</span>=0</span>Set factors equal to 0.<span><span><span>x3</span>=0 or 2x2+1</span>=0</span><span>x=<span>0</span></span>
Answer:
Wait I only see the part where it says “what is the y-intercept and x-intercept of” but I don’t see an equation :/
Step-by-step explanation:
