I'm assuming the equation is x^3 = 216 or
(both mean the same thing)
If so, then the solution to x^3 = 216 is
x = 6
<span>We can find this by taking the cube root of both sides
</span>x^3 = 216
x = 216^(1/3) .... 1/3 power means cube root
x = 6
Checking the answer:
x^3 = 216
6^3 = 216
6*6*6 = 216
216 = 216
Answer is confirmed
So once again
the answer is x = 6. This is assuming the initial assumption made at the top of the problem holds up.
Answer:
x=10
Step-by-step explanation:
first substitute y with the value (-5)
2x+5(-5)=-5 which is simplified to 2x+-25=-5
add 25 to -5 which gives you 2x=20
then divide 20 by 2 which makes x=10
F(x) = 6(9)^x
f(1/2) = 6(9)^(1/2)
f(1/2) = 6(9)^(0.5)
f(1/2) = 6*(9^0.5) 9^0.5 = √9 = +3 or -3.
f(1/2) = 6*3 = 18 or 6*-3 = -18
f(1/2) = 18 or -18
Hope this helps.
The answer to this question is the letter "A" which is $20.70. The solution is shown below:
If the guy will solely use the car, his expenses for the gasoline per month is:
Guy alone = $ 2.76/gallon * 15 gallons = $ 41.4
If the guy will let his two officemates ride the car and contribute each quarter of the of a tank:
First officemate = 15/4 * $2.76 = $ 10.35
Second officemate = 15/4 * $2.76 = $10.35
The guy total savings is shown below:
Total savings = $41.4 - $10.35 -$10.35
Total savings = $20.70
The answer is the letter "A".
Answer:
the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403
Step-by-step explanation:
P( x > 193) = 0.15
= 1- p(x less than or equal 193)
= 1 -p( z < (x- u) /sigma)
= 1- p( z< (193 - 187)/ sigma)
= 1- p( z< 6/ sigma)
P(z< 6/sigma) = 1 - 0.15
P(z < 6/sigma)= 0.85
6/sigma =1.036
Sigma= 6/1.036
Sigma= 5.79
P( x> 185) = 1- p( x< 185)
= 1- p (z < (185- 187)/5.79)
= 1- p( z< -0.345)
= 1- 0.365
= 0.635
P (x> 185) = 0.635 × 0.635
=0.403
