What is the value of u?

X - y = 2 4x – 3y = 11

swat32

Answer:

For x - y = 2

You need to find x or y in one of the equations and then substitute that into the other.

So we have;

x-y=2

4x-3y=11

We will take the first equation and find x;

x-y=2

add y to both sides;

x-y+y=2+y

x=2+y

Now we take that answer and substitute it forx in the other equation;

4(2+y)-3y=11

8+4y-3y=11

8+y=11

y=3

Now we have what y equals, so we use it in the first equation to find x;

x-3=2

x=5

So we have;

x=5; y=3

Hope you understand!

=)

And for 4x – 3y = 11

Multiply the first equation by 2 and the second by 3 so that there are the same number of y's in each:

8x - 6y = 22 ...(3)

30x + 6y = -3 ...(4)

Now add (3) and (4) term by term:

38x + 0 = 19

or

38x = 19

or x = 1/2

Put this back into equation (1)

4*(1/2) - 3y = 11

or

2 - 3y = 11

Subtract 2 from both sides:

-3y = 9

Divide both sides by -3

y = -3

6 0

3 years ago

Read 2 more answers

=

Liula [17]

$\sqrt{((-6)-(-5))^2 +(9-2)^2}=5\sqrt{2} \approx 7.071$

8 0

1 year ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

Answer:

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

Solution:

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago

PLEASE HELP ME!! PLEASE DON'T ANSWER IF YOU ARE NOT PSOTIVE ON WHAT THE ANSWER IS!!!

Talja [164]

Answer:

its A

Step-by-step explanation:

im not gonna step by step it becuase i dont have time but its A

5 0

3 years ago

Read 2 more answers

What is the x-coordinate of the point that divides the

dimaraw [331]

There's a lot of information missing here, and the given list of choices is basically incomprehensible.

Suppose J (a, b) and K (c, d) are two points in the plane. We can trace out the line segment JK joining these points with the function

r(t) = (1 - t) (a, b) + t (c, d)

where 0 ≤ t ≤ 1.

Let P be the point that divides JK into line segments JP and PK having a length ratio of 2:5. Then JP is the point 2/7 of the way along JK, so that the coordinates of P are

P = r(2/7) = 5/7 (a, b) + 2/7 (c, d) = ((5a + 2c)/7, (5b + 2d)/7)

and in particular the x-coordinate of P is (5a + 2c)/7.

6 0

2 years ago