What is the value of u?

For any integers x and y, min(x, y) and max(x, y) denote the minimum and the maximum of x and y, respectively. For example, min(

Annette [7]

Answer:

$min(10,w)=\left \{ {{w} \quad\text{for } w$

Step-by-step explanation:

No value of w is given, so we can only tell you the meaning of min(10, w):

When w < 10, min(10, w) is w.

When w ≥ 10, 10 is the smaller of the two values, so min(10, w) = 10.

3 0

3 years ago

Given the trinomial x^2+bx+c where both the first and second signs are positive, the signs of the factors will be: A. both negat

Lunna [17]

The answer here is C. The sign of the factors are both positive. We can use the FOIL method as reference in determining the sign of the factors. The 3rd term C is positive; therefore our only option is either both negative or both positive. Looking the middle term, which is positive, we know that the middle term is the sum of the outer and inner in FOIL method, which means, signs of the factors must be both positive

7 0

3 years ago

Given f(x) = | – 5 – 4x| ,find the following:

jasenka [17]

Answer:

$f(10) = 35 \\ \\ f( - 11) = 39 \\ \\ f(12) = 53 \\ \\ f(2) = 13$

Step-by-step explanation:

$f(x) = | - 5 - 4x|$

To solve for the following substitute the value of x in the brackets into the above formula and solve for the value of x

NB:  Absolute value of a negative number is the same number but positive.

So we have

$f( - 10) = | - 5 - 4( - 10)| \\ = | - 5 + 40| = 35 \\ \\ f( - 11) = | - 5 - 4( - 11)| \\ = | - 5 + 44| = 39 \\ \\ f(12) = | - 5 - 4(12)| \\ = | - 5 - 48| \\ = | - 53| = 53 \\ \\ f(2) = | - 5 - 4(2)| \\ = | - 5 - 8| = | - 13| \\ = 13$

Hope this helps you

6 0

3 years ago

Read 2 more answers

X=8 f(x)=|x| f(8)=? help me please?

Varvara68 [4.7K]

Is there not more to this problem? maybe thats the final answers

4 0

3 years ago

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

3 years ago