answer.
Answer:
x=2 and y=0 is the required result.
Step-by-step explanation:
We have been given system of equations:
5x+2y=105x+2y=10 (1)
And 3x+2y=63x+2y=6 (2)
We will use elimination method:
Multiply 1st equation by 3 and 2nd equation by 5 we get:
15x+6y=3015x+6y=30 (3)
15x+10y=3015x+10y=30 (4)
Now subtract (4) from (3) we get:
-4y=0−4y=0
y=0y=0
Now, put y=0 in (1) equation:
5x+2(0)=105x+2(0)=10
5x=105x=10
x=2x=2
Hence, x=2 and y=0
Answer:
I got 40210.1
Step-by-step explanation:
4,567.89+7,894.56=12462.45
12462.45+1,232.45=13694.9
13694.9+1,474.10=15169
15169+2,585.20=17754.2
17754.2+3696.36=21450.56
21450.56+3,214.56=24665.12
24665.12+6,545.65=31210.77
31210.77+7,898.78=39109.55
39109.55+1.100.55=40210.1
Answer:
No positive value of n
Step-by-step explanation:
we have to find out for how many positive values of n are both
our-digit integers
Let us consider first cube
we get 4digit lowest number is 1000 and it has cube root as 10.
Thus 10 is the least integer which satisfies four digits for cube.
The highest integer is 9999 and it has cube root as 21.54
or 21 the highest integer.
Considering 3^n we get,
3^10 is having 5 digits and also 3^21
Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.
Answer:
5
Step-by-step explanation:
25/5
5×5=25
5 <---answer