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2 years ago

Which pairs of triangles can be shown to be congruent using rigid motions?

Mathematics

2 answers:

In-s [12.5K]2 years ago

7 0

Here is the answers hope this helps enjoy

Reika [66]2 years ago

4 0

Answer:

1. Not congruent

2. Not congruent

3. Congruent

4. Congruent

Step-by-step explanation:

Accroding to the options:

1. ΔABC is not congruent to ΔMPN.

As, we can see that the distance between AC and the point B is 5 units. If we rotate ΔABC around the point B downwards and then translate it downwards.

We may obtain ΔMPN but, in ΔMPN the distance between MN and point P is 4 units.

So, ΔABC will not be congruent to ΔMPN.

2. ΔABC is not congruent to ΔEGF.

As, we can see that the distance between AC and the point B is 5 units. If we rotate ΔABC around the point B upward and then translate it downwards.

We may obtain ΔEGF but, in ΔEGF the distance between EF and point G is 4 units.

So, ΔABC is not congruent to ΔEGF.

3. ΔABC is congruent to ΔSTU.

As, we can see that the distance between AC and the point B is 5 units. If we reflect ΔABC around the line AC and then translate it 5 units to left. We obtain ΔSTU.

So, ΔABC is congruent to ΔSTU.

3. ΔEFG is congruent to ΔMNP.

As, we can see that the distance between EF and the point G is 4 units. If we reflect ΔEFG around the line EF and then translate it 4 units to downwards. We obtain ΔMNP.

So, ΔEFG is congruent to ΔMNP.

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2 years ago

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The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

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The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

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