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2 years ago

Need help please!! I’m confused

Mathematics

1 answer:

trapecia [35]2 years ago

4 0

Answer:

y = -0.2x + 3.8

Step-by-step explanation:

it states it has been 7 weeks. 0.2 x 7 is 1.4. That means they started with 2.4 + 1.4 meters thick of ice sheet, which is 3.8, which is the number they started with. So, b = 3.8 and it says it melts 0.2 so it's a negative, which is -0.2 as slope. So, y = -0.2x + 3.8

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Consider the matrices -2 -1 1 4 1 A = B = 4 -2 4 -2 -2 4 -2 1 -1 (a) Verify that they are diagonalizable and that they commute.

Phoenix [80]

Answer:

Explanation to answers are shown in the attachment

Step-by-step explanation:

This is a long solution but the detailed step by step and appropriate mathematical manipulation has been done as shown in the attachment.

6 0

3 years ago

PLEASE HELPPPP! 50 points, my brain has been doing homework all night and this is simple math ;-; I just cant think rn its 7th g

LenKa [72]

Answer:

68/.75

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7 0

3 years ago

Please help me idk this

Pachacha [2.7K]

Answer:

x = 35 degrees

Step-by-step explanation:

the little box on the left side of the ttriangle means that is a 90 degrees angle.

So you add 55 + 90 = 145

Then subtract 180 - 145

which gives you 35

4 0

3 years ago

Read 2 more answers

What are the vertices of A'B'C produced by T (A'B'C)=ABC?

Valentin [98]

They are up and down and left and right

5 0

3 years ago

During halftime of a basketball game, a sling shot launches T-shirts at the crowd. A T-shirt is launched from a height of 4 f

Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is $4 + 64\cdot t - 16 \cdot t^{2}$

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

$h = h_1 + u\cdot t - \frac{1}{2} \cdot g \cdot t^{2}$

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

$h = 4 + 64\times 2 - \frac{1}{2} \times 32 \times 2^{2}$

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

$h = h_1 + u\cdot t - \frac{1}{2} \cdot g \cdot t^{2}$

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

$h =4 + 64\cdot t - \frac{1}{2} \times 32 \cdot t^{2} = 4 + 64\cdot t - 16 \cdot t^{2}$ .

6 0

3 years ago