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Fantom [35]
3 years ago
12

−1.64 as a mixed number in simplest form.

Mathematics
1 answer:
liraira [26]3 years ago
4 0
Convert to a mixed number by placing the numbers to the right of the decimal over 100. Reduce the fraction. Then, convert the mixed number to an improper fraction by multiplying the denominator by the whole number and adding the numerator to get the new numerator. Place this new numerator over the original denominator.

-41\25
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An x-ray machine for animals cost $125,000. if the loan is for 10 years, and the interest paid is $65,625, what's the interest r
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3 0
3 years ago
12−(−2) over a line 12−6÷2
joja [24]

Given 12−(−2) over a line 12−6÷2

We can use PEMDAS rule and solve the expression in the order as given below:-

1. Parentheses

2. Exponents

3. Multiplication

4. Division

5. Addition

6. Subtraction

Now solving for given expression:-

\frac{12-(-2)}{12-(\frac{6}{2})}\\\\=\frac{12+2}{12-3}\\\\=\frac{14}{9}

So final answer is 14/9 i.e. 14 over 9.

7 0
3 years ago
Maurice averaged 79 points for 6 tests. How many more points must he score in the next text to raise his average to 80.
Lady bird [3.3K]

Answer:

86 is the score that Maurice must get to average his score to 80

8 0
1 year ago
If ORBIT is coded BEOVG, then how is PLANET coded? /
arlik [135]

Answer:

1. CYNARG

Step-by-step explanation:

This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:

C = (P + o) \text{mod} 26

In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.

Finding the offset:

O is coded B

O is the 15th letter in the alphabet, so P = 15.

B is the 2nd letter in the alphabet, so C = 2

C = (P + o) \text{mod} 26

2 = (15 + o) \text{mod} 26

|o = |2-15| \text{mod} 26

o = 13

So

C = (P + 13) \text{mod} 26

PLANET:

P

P is the 16th letter in the alphabet.

C = (16 + 13) \text{mod} 26 = 3

So P is coded C.

L

L is the 12th letter in the alphabet:

C = (12 + 13) \text{mod} 26 = 25

L is coded Y(25th letter in the alphabet)

A

A is the 1st letter in the alphabet

C = (1 + 13) \text{mod} 26 = 14

A is coded N

N

N is the 14th letter in the alphabet

C = (14 + 13) \text{mod} 26 = 1

N is coded A

E

E is the 5th letter in the alphabet

C = (5 + 13) \text{mod} 26 = 18

E is coded R

So the correct answer is:

1. CYNARG

4 0
3 years ago
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