What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
Answer:
i believe the answer is B
Step-by-step explanation:
make 2 and 2/3 a decimal
2 divided by 3 will give you .6 repeating. just round to .8
then divide 48 by 2.8
it will give you 17.142
i just rounded it to 18... bc its so close to it
<u>hope this helps :)</u>
Answer:
1/4
Step-by-step explanation:
i think you would add 5+4+3 and 2+3+4 and divide them so 9/12 and that makes your probability which leaves a 3/12 chance non of them are in favour of the book
You do nine divided by fifteen which =$0.6
Answer:
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