Find the rate of change of the area of a square with respect
1 answer:
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Answer:
x(log(x) - 1) + C
Step-by-step explanation:
The formula for the derivative of a logarithm function is:
For your case, the base is 10. Now that we have the derivative, lets use integration by parts. I will be differentiating log(x) and integrating 1:
u = log(x)
du = dx/xlog(10)
dv = 1
v = x
You get:
log(x)x - integral(dx/log(10))
Therefore the answer is:
log(x)x - x/log(10) + C
x(log(x) - 1) + C