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Genrish500 [490]
3 years ago
15

Find the rate of change of the area of a square with respect

Mathematics
1 answer:
Romashka [77]3 years ago
4 0
Let the side length of the square be x, then A = x^2
but diagonal (z) = sqrt(2x^2)
z^2 = 2x^2
x^2 = 1/2 z^2

Thus, A = 1/2 z^2
dA/dz = 1/2 (2z) = z
The rate of change is z.

When z = 4, the rate is 4.
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Evan and Eileen Carter are husband and wife and file a joint return for 2019. Both are under 65 years of age. They provide more
S_A_V [24]

Answer:

The correct answer is b) four.

Step-by-step explanation:

Evan and Eileen Carter must submit a separate statement as dictated by the requirements for the claim.

In the case of the daughter, she no longer meets the requirement of a qualified child because she is over 24 years old; but qualifies as an eligible relative, and also, the income of her scholarship is not enough, so she needs the help of her parents to cover her expenses.

The couple also provides support in all expenses of Evan's                    great-grandmother; although Belinda lives in an asylum, the Carter can claim the exemption since, for qualified relatives, they do not ask as a mandatory requirement that they live in the same place.

And finally, Peggy cannot request an exemption since she is not a qualified relative, so she does not fall within the exceptions to claim, even if she lives in Evan and Eileen Carter´s house.

Therefore, the Carter can claim four dependency exemptions, one for each person that are Evan, Eileen, Pamela, and Belinda.

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<em>I hope this information can help you.</em>

7 0
3 years ago
Can some one do all these questions for me.
Zielflug [23.3K]
Which questions can you please send a link? :)
6 0
3 years ago
As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim
AlekseyPX

Answer:

0.44

Step-by-step explanation:

Given the estimated logistic regression model on risk of having squamous cell carcinoma

-4.84 + 4.6*(SMOKER)

SMOKER = 0 (non-smoker) ; 1 (SMOKER)

What is the predicted probability of a smoker having squamous cell carcinoma?

exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))

SMOKER = 1

exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)

exp^(-0.24) / (1 + exp^(-0.24))

0.7866278 / 1.7866278

= 0.4402863

= 0.44

3 0
3 years ago
Given the two graphs below, identify in two complete sentences one similarity and one difference between the graphs.
Advocard [28]

Answer:

well one similarity is that they both cross over zero and one difference is that one is going verticl and one is going up and down

Step-by-step explanation:

7 0
2 years ago
Solve for X please help I need this asap
natka813 [3]

Answer:

f

Step-by-step explanation:

fgbdf

8 0
3 years ago
Read 2 more answers
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