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1 year ago

Write an equation in point-slope form of the line that passes through the given point and with the given slope m. (-3,1);m=6

1 answer:

7 0

The required equation in point-slope form of the line that passes through the given point (-3,1) is y=6x + 19 in point slope form that has slope =6 .

<h3>What is slope?</h3>

Numerical measure of a line's inclination relative to the horizontal. In analytic geometry, the slope of any line, ray, or line segment is the ratio of the vertical to the horizontal distance between any two points on it.

Given:

The given points of the line is

(-3,1)

m=6

According to given question we have

By the slope of the equation we get

y=mx + c

1=(6)(-3) + b

1+18= b

b=19

The equation is y=6x + 19.

Therefore, the required equation in point-slope form of the line that passes through the given point (-3,1) is y=6x + 19 in point slope form that has slope =6 .

Learn more details about slope here:

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OMG can someone please help me solve this problem

klasskru [66]

The correct answer is A.) { - 0.79 ; 1.08 }, because
 For ax^2 + bx + c = 0, the value of x is given by: ;
a = - 7 ; b = 2 ; c = 6 ;
b^2 - 4ac = 4 + 168 = 172 ; $\sqrt{172}$ ≈ 13.11 ;
x 1 = ( - 2 + 13.11 ) / (- 14) = 11.11 / ( - 14 ) ≈ -0.79 ;
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3 years ago

My cat weighs 80 N. The area of the bottom of her foot is approximately 0.0045 m(squared). if she stands on one foot and lost ha

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Answer:

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4 years ago

Find the distance UV between the points U(4,−2) and V(6,−1). Round your answer to the nearest tenth, if necessary.

Liono4ka [1.6K]

The horizontal distance is the difference of x-coordinates: 6 - 4 = 2.

The vertical distance is the difference of y-coordinates: -1 - (-2) = 1.

The straight-line distance (d) can be found using the Pythagorean theorem, since the vertical and horizontal distances are at right angles to each other.

.. d² = 2² + 1² = 5

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The distance UV is about 2.2.

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3 years ago

Given: line AB is congruent to line CD and line AD is congruent to line BC. Prove: angle D is congruent to angle B

torisob [31]

AD = BC ----> Parallel lines
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6 0

3 years ago

Read 2 more answers

Anna went from home to school with the speed 3 km/hour. She ran back home with the speed 6 km/hour.Her sister Olga went to schoo

PIT_PIT [208]

Let:
v = Olga's speed
t = the time Anna spent going to school (3 km/hour)
t/2 = the time Anna spent running back home with speed of 6 km/hour
So, t + t/2 = 3t/2 is the total time
In the meantime distance = speed*time and the both made the same distance we can put it as:
3t + 6*(t/2) = (3t/2)*v
6t = (3/2)tv divide both sides by t
(3/2)v = 6
v = 2*6/3
v = 4 km/hour
Olga's speed was 4 km/hour.

3 0

3 years ago

Write an equation in​ point-slope form of the line that passes through the given point and with the given slope m. (-3,1);m=6

Write an equation in point-slope form of the line that passes through the given point and with the given slope m. (-3,1);m=6