Explanation:
think so it is useful and sufficient for your question
The mass of magnesium chloride produced is calculated as follows
write the equation for reaction
Mg +2HCl=MgCl +H2
find the moles of each reactant
moles = mass/molar mass
moles for mass = 32.5 g/24.3 g/mol= 1.34 moles
moles for HCl = 32.5g / 95.3 g/mol=0.89 moles
HCl is the limiting reagent hence by use of mole ratio between HCl to MgCl2 which is 2:1 the moles of MgCl2 is therefore = 0.89/2 =0.445 moles
mass of MgCl2 is therefore= moles/molar mass
=0.445moles x 95.3 g/mol= 42.4 grams of MgCl2
Answer:
Ethanol = 102.29 g
Carbon Dioxide = 97.71 g
Solution:
The Balance Chemical Equation for the fermentation of Glucose is as follow,
C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂
Mass of Ethanol produced:
According to equation;
180.156 g (1 mole) C₆H₁₂O₆ produces = 92.14 g (2 moles) of C₂H₅OH
So,
200 g of C₆H₁₂O₆ will produces = X g of C₂H₅OH
Solving for X,
X = (200 g × 92.14 g) ÷ 180.156 g
X = 102.29 g of C₂H₅OH
Mass of Carbon Dioxide produced:
According to equation;
180.156 g (1 mole) C₆H₁₂O₆ produces = 88.02 g (2 moles) of CO₂
So,
200 g of C₆H₁₂O₆ will produces = X g of CO₂
Solving for X,
X = (200 g × 88.02 g) ÷ 180.156 g
X = 97.71 g of CO₂