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guapka [62]
4 years ago
9

Does mint really cool your breath? doing a science fair and also is there three good questions i could use for the topic?

Chemistry
2 answers:
PilotLPTM [1.2K]4 years ago
8 0

Answer:

Yes it does.

Explanation:

Ne4ueva [31]4 years ago
5 0

Answer:

I wil say yes mint really cool your breath

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True of false an unbalanced force cannot change the direction in which an object is moving
Andrei [34K]
False. An unbalanced force can change the direction in which an object is moving.
4 0
4 years ago
What is the indepent variable
Gwar [14]
It is a variable that does not count on others help.
7 0
3 years ago
What temperature will the water reach when 10.1 g CaO is dropped into a coffee cup containing 157 g H2O at 18.0°C if the followi
Zepler [3.9K]

Answer:

Final temperature attained by water = 34.6°C

Explanation:

The reaction of CaO and H₂O is an <em>exothermic reaction</em>. The equation of reaction is given below:

CaO + H₂O ----> Ca(OH)₂

The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol

Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g

Number of moles of CaO = 10.1g/56g/mol =0.179moles

Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol

Using the formula, <em>Quantity of heat, q = mass * specific heat capacity * temperature rise.</em>

mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C

Final temperature(T₂) - Initial temperature(T₁) = Temperature rise

11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)

11599.2 = 698.478T₂ - 12572.604

11599.2 + 12572.604 = 698.478T₂

698.478T₂ = 24171.804

T₂ = 34.6°C

Therefore, final temperature attained by water = 34.6°C

6 0
3 years ago
Please answer these!!!
olasank [31]

Answer:

1.b. 2.5  mol

2.c.82.8%

3.d. synthesis

4.c . 2:2

5.d. 5 moles

6.c.5.02

7.d.3:1

8.d.2.68 moles

Explanation:

1.

2RbNO_{3}\rightarrow 2RbNO_{2}+1O_{2}

Here , 2 mole of RbNO3 will produce, 1 mole of O2

1 mole of RbNO3 will produce =

\frac{1}{2} mole of O2

5 mole of RbNO3 will produce =

\frac{1}{2}\times 5

<u>= 2.5 mole of O2</u>

2 .

Molar mass of HCl = 1 + 35.45 = 36.45 gram

Molar mass of CO2 = 12 +32 = 44 gram

1 mole of the substance = molar mass

So , 1 mole of HCl = 36.45 gram

2 mole of HCl = 2 x 36.45 =72.9 gram

1 mole of CO2 = 44 gram

The given equation is :

CaCO_{3}+2HCl\rightarrow CO_{2}+H_{2}O

Here CaCO3 is the excess reagent and HCl is the limiting reagent

2 mole of HCl will produce = 1 mole of CO2

72.9 gram of HCl= 44 gram of CO2

so, 1 gram of HCl =

\frac{44}{72.9} gram of CO2

Here we need to calculate the mass of CO2 in 200 gram of HCl.

So, 200 gram of HCl =

\frac{44}{72.9}\times 200 gram CO2

=120.71 gram CO2

this is the theoritical yield of CO2 = 120.71 gram

Experimental yield = 100 gram (given)

The percent yield is calculated by:

=\frac{Experimental}{Theoritical}\times 100

=\frac{100}{120.71}100

= 82.84%

3.Synthesis Reaction : Those reactions in which two or more substances combine to give a single product.

Here NH3 and HCl are combined and giving only one product = NH4Cl

4.

2H_{2}+1O_{2}\rightarrow 2H_{2}O

Hydrogen = H2

Water = H2O

Here Ratio of H2 to H2O is 2:2

5.The balanced equation is :

1Ca(OH)_{2}+2HCl\rightarrow 1CaCl_{2}+2H_{2}O

The number of atoms on left side should be equal to the right side:

Ca = 1

H = 4

O = 2

Cl = 2

Here, 2 moles of water(H2O) = 2 moles of HCl

So, 5 moles of water will give = 5 moles of HCl

6.

2Ag(NO)_{3}+BaCl_{2}\rightarrow 2AgCl_{2}+BaNO_{3}

Molar mass of AgNO3 = 169.87 g/mol

1 mol of AgNO3 = 169.87 gram

Molar mass of AgCl = 143.32 g/mol

1 mole of AgCl = 143.32 grams

According to the given equation ,

2 mole of AgNO3  will give = 2 mole of AgCl

1 mole of AgNO3 = 1 mole of AgCl

169.87 gram of AgNO3 = 143.32 gram of AgCL

1 gram of AgNO3 =

\frac{143.32}{169.87}

5.95 gram of AgNO3 =

\frac{143.32}{169.87}\times 5.95

= 5.02 grams

7. The mole ratio of Hydrogen (H2) to Nitrogen (N2):

N_{2}+3H_{2}\rightarrow 2NH_{3}

H2 = 3 mole

N2 = 1 mole

[H2]:[N2] = 3:1

8. The moles in a substance can be calculated by using :

moles=\frac{Mass}{Molar\ mass}

Mass of N2 = 75 grams (Given)

Molar mass = 28 gram

moles=\frac{75}{28}

Moles = 2.678 moles

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