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rosijanka [135]
3 years ago
13

The Calories on a food label indicate the

Chemistry
1 answer:
marusya05 [52]3 years ago
5 0

Answer:

chemical energy

Explanation:

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3. Complete the following table.
Vinil7 [7]
Li and CI or C and H
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3 years ago
Which ionic compound is soluble in water pbbr2, fe (oh)3,ca(no3)2, baso4?
Anton [14]

Ionic compound are those compounds which are made up of ions. The ion which has tendency to loose electrons is said to cation (positive charge) such as metals whereas ion which has tendency to gain electrons is said to anion (negative charge) such as non-metals.

Calcium nitrate is quite soluble in water due to very low lattice enthalpy in comparison to other ionic compound. With lower lattice enthalpy, less energy is required for the dissociation of calcium nitrate and it get dissolves in water than other three compounds. Moreover, hydration energy is higher for calcium nitrate which make its solubility higher in water than other ionic species.

Thus, Ca(NO_{3})_{2} is correct answer.

5 0
3 years ago
What is the structure of beeswax that contains 16 carbon of carboxylic acid and 30 carbon of alcohol?
melisa1 [442]
This is the answer hope this helps

7 0
3 years ago
Read 2 more answers
What happens when a solid compound dissolves in water?
IRINA_888 [86]
It becomes a liquid with the water

6 0
3 years ago
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At 25.0°c, a solution has a concentration of 3.179 m and a density of 1.260 g/ml. the density of the solution at 50.0°c is 1.249
oksano4ka [1.4K]

Answer: -

3.151 M

Explanation: -

Let the volume of the solution be 1000 mL.

At 25.0 °C, Density = 1.260 g/ mL

Mass of the solution = Density x volume

= 1.260 g / mL x 1000 mL

= 1260 g

At 25.0 °C, the molarity = 3.179 M

Number of moles present per 1000 mL = 3.179 mol

Strength of the solution in g / mol

= 1260 g / 3.179 mol = 396.35 g / mol (at 25.0 °C)

Now at 50.0 °C

The density is 1.249 g/ mL

Mass of the solution = density x volume = 1.249 g / mL x 1000 mL

= 1249 g.

Number of moles present in 1249 g = Mass of the solution / Strength in g /mol

= \frac{1249 g}{396.35 g/mol}

= 3.151 moles.

So 3.151 moles is present in 1000 mL at 50.0 °C

Molarity at 50.0 °C = 3.151 M

7 0
3 years ago
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