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2 years ago

Need answer for this ratios question

Mathematics

1 answer:

Tom [10]2 years ago

7 0

Answer: 4:1

Step-by-step explanation: I think the answer is 4:1. I think this because 20% of 2500, would be 500. So 2500-500=2000. So the ratio would be 2000:500. Then we simplify 2000:500, by dividing 2000 by 500, and dividing 500 by 500. 500 / 500 = 1. 2000 / 500 = 4, so the answer is 4:1. (I am sorry if I am incorrect)

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If five notebooks cost $5.25 how much would 3 cost?

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3 years ago

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Please help and thank you

tresset_1 [31]

Answer:

A. The description represents an arithmetic sequence because the successive y-values have a common difference of 600

Step-by-step explanation:

The equation that this situation is describing would be

$y=600x+20000$

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3 years ago

Choose any positive integer. Powers of two here are not very interesting, so choose something else. If the number you have chose

Yakvenalex [24]

Answer:

Step-by-step explanation:

Let the integer be 6 for even and 7 for odd (say)

For 6, we divide by 2, now get 3. Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16. Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.

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Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.

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3 years ago

Helppppp and show equation plsssssssss

laiz [17]

Answer:

Step-by-step explanation:

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3 years ago

Suppose that receiving stations X, Y, and Z are located on a coordinate plane at the points (4,5), (-6,-6), and (-14,2

Lilit [14]

Answer:

(-2, -3)

Step-by-step explanation:

A careful graph shows the point (-2, -3) is at the intersection of the circles whose radii are the given distances from the receiving stations.

_____

The simultaneous equations for the circles can be solved algebraically.

The epicenter is 10 units from X, so lies on the circle ...

(x -4)^2 +(y -5)^2 = 10^2

x^2 -8x +16 +y^2 -10y +25 = 100

x^2 +y^2 -8x -10y = 59

The epicenter is 5 units from Y, so lies on the circle ...

(x +6)^2 +(y +6)^2 = 5^2

x^2 +12x +36 +y^2 +12y +36 = 25

x^2 +y^2 +12x +12y = -47

The epicenter is 13 units from Z, so lies on the circle ...

(x +14)^2 +(y -2)^2 = 13^2

x^2 +28x +196 +y^2 -4y +4 = 169

x^2 +y^2 +28x -4y = -31

Subtracting the second equation from each of the other two, we get ...

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-20x -22y = 106 . . . . eq1 -eq2

(x^2 +y^2 +28x -4y) -(x^2 +y^2 +12x +12y) = (-31) -(-47)

16x -16y = 16 . . . . . . . .eq3 -eq2

These simultaneous linear equations can be solved a variety of ways. We might use substitution:

x = y+1 . . . . . from eq3 -eq2 divided by 16

10(y +1) +11y = -53 . . . . . from eq1 -eq2 divided by -2

21y = -63 . . . . . . . . . . . . simplify, subtract 10

y = -3

x = y+1 = -2

The epicenter is located at (x, y) = (-2, -3).

8 0

3 years ago