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Kruka [31]
3 years ago
8

I need help with this

Biology
1 answer:
ser-zykov [4K]3 years ago
7 0
1. gamete
2. Genes, DNA, Chromosomes, Nucleus
3. Chromosomes are found in many places in the cell 
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This is true. Hope this helps.
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I NEED QUICK BIOLOGY HELP!
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D  lowering the activation energy of a reaction.
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Quade is studying for an exam, which will cover neurons and action potentials. He has drawn a diagram that shows the segments of
VMariaS [17]

Answer: positive sodium ions

Explanation:

This relates to the Action Potential which is what a nerve cell goes through when it needs to send information down the nerve cell to another cell and so on till it gets to the destination of the message.

The information is transmitted when the segments of the axon fire and when they do, positive sodium ions come in from outside the cell to the inside thereby making the inside positive. The previous segment would return to a resting potential when potassium ions which are negative, rush into the cell.

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3 years ago
Albinism in humans is caused by homozygosity for mutant recessive alleles of the tyr gene, which is located on chromosome 11. al
yanalaym [24]
Exactly 989527/1048576, or approximately 94.37%  
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB 
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So 
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%  
So the answer is exactly 989527/1048576, or approximately 94.37%
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The myxomycota and acrasomycota begin their lives as _______.
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