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3 years ago

The sacrum articulates with the The sacrum articulates with the ilium and ischium. pubis. ilium. ischium and pubis. ischium.

Biology

1 answer:

Svetach [21]3 years ago

6 0

Answer:

The sacrum articulates with the<u> ilium</u>.

Explanation:

The sacrum is a bone formed by the sacral vertebrae, which have fused to give this bone. Above it articulates with the lumbar vertebra, below with the coccyx, which is the last section of the vertebrae column. Lastly, it articulates with the ilium at the sides. The ilium is one of the three bones that makes the hip bone. It is the largest one and in the upper part of the hip bone.

The ischium and pubis, which are the other two bones that form the hip bone, do not articulate with the sacrum, but they articulate with the ilium and with each other.

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How could we make a model of the Milky Way galaxy that shows Earth's location?

iren2701 [21]

Answer:

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Explanation:

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3 years ago

Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based

zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

$p^{2} = f(TLTL)$

$2pq = f(TSTL)$

$q^{2} = f(TSTS)$

So, if the population is in balance:

$P = p^{2}$

$H = 2pq$

$Q = q^{2}$

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

$f(TLTL) = P = p^{2} = 0,4^{2} = 0,16$

$f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48$

$f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36$

I hope you have a SUPER day!

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3 years ago

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Leona [35]

I can’t see the image but I would guess animals such as deer or horse or elephants or any large animal have the ability to run over the rocks and turn them to smaller sediments

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3 years ago

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This image shows a volcanic eruption in Hawaii with lava

liq [111]

Answer:

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Explanation:

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4 years ago

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Answer:

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2 years ago