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3 years ago

14

What are the roots of the equation x^2=5x+14 there are 2 of them show your work

1 answer:

fiasKO [112]3 years ago

5 0

Answer:

The solutions are: $x=7$ or $x=-2$ .

Step-by-step explanation:

The given equation is $x^2=5x+14$

We rewrite in the standard quadratic form to obtain;

$x^2-5x-14=0$

We split the middle term with -7,2 because their product is -14 and their sum is -5.

$x^2-7x+2x-14=0$

Factor by grouping;

$x(x-7)+2(x-7)=0$

$(x-7)(x+2)=0$

Either $(x-7)=0$ or $(x+2)=0$ .

Either $x=7$ or $x=-2$ .

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Answer:

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Step-by-step explanation:

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Where:

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The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

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$\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|$

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The approximate difference in the half-lives of the isotopes is 66 days.

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