Question

What are the roots of the equation x^2=5x+14 there are 2 of them show your work

Answer 1

Answer:

The solutions are: $x=7$ or $x=-2$.

Step-by-step explanation:

The given equation is $x^2=5x+14$

We rewrite in the standard quadratic form to obtain;

$x^2-5x-14=0$

We split the middle term with -7,2 because their product is -14 and their sum is -5.

$x^2-7x+2x-14=0$

Factor by grouping;

$x(x-7)+2(x-7)=0$

$(x-7)(x+2)=0$

Either $(x-7)=0$ or $(x+2)=0$.

Either $x=7$ or $x=-2$.