Answer:
The equation of tangent plane to the hyperboloid
.
Step-by-step explanation:
Given
The equation of ellipsoid

The equation of tangent plane at the point 
( Given)
The equation of hyperboloid

F(x,y,z)=


The equation of tangent plane at point 

The equation of tangent plane to the hyperboloid

The equation of tangent plane

Hence, the required equation of tangent plane to the hyperboloid

Answer:
7.193 ft
Step-by-step explanation:
|\
| \
| \
| \
h | \ 10 ft
| \
| \
| 46° \
---------------------
For the 46° angle, h is the opposite leg. The hypotenuse is 10 ft. The sine is the trig ratio that relates the opposite leg to the hypotenuse.
sin A = opp/hyp
sin 46° = h/10
h = 10 sin 46°
h = 7.193
Answer: 7.193 ft
I’m pretty sure it would be the third option, 162