Answer:
We are given the following in the question:
where P(x) in millions is the number of U.S. travelers from 1990 through 2009 and x = 1 represents 1991.
We have to approximate the number of U.S. travelers to other countries in each given year.
(a) 1990
We put x = 0 in the given function.
Thus, there are 48.09 millions U.S. travelers in 1990.
(b) 2000
We put x = 10 in the given function.
Thus, there are 56.888 millions U.S. travelers in 2000.
(c) 2009
We put x = 19 in the given function.
Thus, there are 31.085 millions U.S. travelers in 2009.
Step-by-step explanation:
Hope this helps:) plz mark as brainliest I really need it:)
Answer:
He must score 83 in the last test.
Step-by-step explanation:
To get a mean of 80 Terry must score a total of 4*80 = 320 over the 4 tests.
So his score for the last test must be 320 - (71 + 80 + 86)
= 320 - 237
= 83.
This would be:

Using common denominator of 6:

They should use

of their time.
Answer:
Step-by-step explanation:
First get the answer to -3n - 4 = 2
-3n - 4 + 4 = 2 + 4
-3n = 6
n = 6/-3
n = -2
That answer is the only one that is permitted. It is the only one that completely satisfies the equation.
Now when you do the inequality, look what happens.
-3n - 4 < 2 Add 4 to both sides.
-3n-4+ 4 < 2+4
-3n < 6 Now there are a bunch of ways (2) to solve this.
No matter which way you do it, the arrow will change.
-3n/-3 > 6/-3
n > - 2
That means that any number that is greater than - 2 will satisfy the inequality.
So n = 0 will work. Even n = - 1 will work. Anything bigger than -2 will work. The equation does not provide that kind of latitude.
Answer:
Percent change = 5.4%
Step-by-step explanation:
Given:
Number of students voted last year = 762
Number of students voted this year = 721
Change in the number of students who voted from last year to this year is given by the difference of their number. This gives,
Change in the number of students that voted = 762 - 721 = 41
Now, percentage change in the number of students that voted is given as:

Therefore, the percent change in the number of students that voted is 5.4%.