Answer:
There are no vertical asympotes for this rational function.
Step-by-step explanation:
For rational functions, a vertical asymptote exists for every value of the independent variable such that function become undefined, that is, such that denominator is zero. Let be the following rational function:
, 
There is a vertical asymptote for this case:


Which is out of the interval given to the rational function. Hence, we conclude that there are no vertical asympotes for this rational function.
Its Letter A see photo for solution
Concave up is U-shaped.
There will be a inflection/critical point f'(x) =0 then a negative slope f'(x) = neg then another inflection/critical point f'(x) =0 at the bottom of the U-shape then a positive slope to last inflection/critical point. The interval for the Concave Up shape is the first and last inflection points.
We have the same workbook lol
The answer is
Drums: 2/4
milks 4/9
(unless your teacher wants it improper.)