V = 1/3* h * r^3 pi
V ' = 1/3* h/3* (2r)^3 pi = h/9 * 8r^3 * pi
V ' / V = (h/9 * 8r^3 * pi) ÷ ( 1/3* h * r^3 pi ) = (8 * 3)/ 9 = 8 /3
Answer:
A
Step-by-step explanation:
Well considering how the graph looks, from the x-axis(0,0), the line(x) moves upwards on the left before itf(x) moves downwards on the right
The domain is the set of allowed x inputs, or x coordinates of a function. In this case, any point on the curve has an x coordinate that is 4 or smaller.
Therefore, the domain is the set of numbers x such that 
To write this in interval notation, we would write ![(-\infty, 4]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%204%5D)
This interval starts at negative infinity and stops at 4. We exclude infinity with the curved parenthesis and include 4 with the square bracket.
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The range is the set of possible y outputs. Every point on this curve has a y coordinate that is either 0 or it is larger than 0.
The range is the set of y values such that 
In interval notation, it would be written as 
This time we start at 0 (including this endpoint) and "stop" at infinity
note: we always use curved parenthesis at positive or negative infinity because we cannot reach either infinity
Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
The other line extends slightly down and to the right to point E
