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Sunny_sXe [5.5K]
3 years ago
9

Help I’m really bad at this

Mathematics
1 answer:
kogti [31]3 years ago
4 0

Answer:

72

Step-by-step explanation:

The formula for surface area is SA = 2lw + 2wh + 2lh

W = width

L= length

H = height

A = 2(wl + hl + hw)

2·(6·3+2·3+2·6)

Simplify that down to get the answer 72

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What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2, 4)?
Aneli [31]

Answer: 5x + 2y = -2

Step-by-step explanation:

Change 5x+2y=12 to slope intercept: 2y = 12 - 5x, y = -5x/2 + 6

A parallel line has the same slope, so the line we try to find is y = -5x/2 + b.

Substitute (-2, 4) in and get 4=5+b, so b = -1.

Therefore the answer is y = -5x/2 - 1, or if you want it in the original form it would be 2y = -5x - 2 ---> 5x+2y = -2.

Hope that helped,

-sirswagger21

7 0
3 years ago
Help would be appreciated​
Vesnalui [34]

Answer:

<u>5x+10</u>

27x

Step-by-step explanation:

cross multiply

4 0
3 years ago
Please help me with this question
Andreyy89

Answer:

the slope is -3, the slope is negative, the y-intercept is 0

Step-by-step explanation:

this ones are the ones that apply to the graph

4 0
3 years ago
Read 2 more answers
Darren has the option of investing in either Stock A or Stock B. The probability of the return of Stock A being 25% is 0.45, 14%
Lunna [17]

Answer:

C)A is 15.95% ,B is 11.85%

Step-by-step explanation:

We know that the expected value in probability distribution is given as

Lets X is the expected value then

X= \sum_{i=1}^{i=n} X_i P_i

For stock A

X=0.25 x 0.45+0.14 x 0.25+0.04 x 0.3

X=0.1595

So the expected return for A is 15.95%

For stock 9

X=0.3 x 0.3+0.09 x 0.25+0.02 x 0.3

X=0.1185

So the expected return for B is 11.85%

So our option C will be the answer of that problem.

8 0
3 years ago
Which statements are true about the linear inequality y &gt; 3/4x – 2? Check all that apply. The slope of the line is –2. The gr
pishuonlain [190]
You can draw the area bounded by the unequality y\ \textgreater \  \frac{3}{4} x-2 in following way:

1. Draw a dashed line y=\frac{3}{4} x-2 with a slope \frac{3}{4} (a dashed, because all points from this line, for example when x=0, y=-2 do not belong to the area);

2. Define which part (under the line or over the line) is suitable by substituting values. For example, when x=0 and y=0 you obtain that 0\ \textgreater \  \frac{3}{4} \cdot 0-2 is a right unequality, that means that the point (0,0) is a solution and belongs to the area;

3. Shade that part of the plane to which point (0,0) belongs, you receive the area over the line (see image).

From the done steps you can see that only fourth statement is true.



4 0
3 years ago
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