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zavuch27 [327]
3 years ago
6

Translate the following into an algebraic expression:

Mathematics
1 answer:
natka813 [3]3 years ago
4 0

For this case we have the following variables:

x: number of hours that it takes Mr. David to complete a job working alone.

y: number of hours it takes Mr. Ludwing to complete a job working alone.

k: number of hours it takes for both of them to do a job working together.

We now write the equation that models the problem.

To do this, we must add the work rate per hour of each and equal to the rate of work per hour of both.

\frac{1}{x} +\frac{1}{y} =\frac{1}{k}

We have then:

Answer:

The algebraic expression that models the problem is:

\frac{1}{x} +\frac{1}{y} =\frac{1}{k}

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Find the product of this question down below
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\large\boxed{D)\ \dfrac{8}{7}}

Step-by-step explanation:

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4 0
3 years ago
What vaule of x makes th question true? 3x+2(x-5)=50 a. 8 b.9 c.11 d.12
Ainat [17]
Hey Tierra7l, 

Lets solve your equation together step by step. 

3x+2\left(x-5\right)=50 

\mathrm{Expand}\:2\left(x-5\right):\quad 2x-10 

\mathrm{Distribute\:parentheses\:using}:\quad \:a\left(b+c\right)=ab+ac 

                                    a=2,\:b=x,\:c=-5 

2\cdot \:x+2\left(-5\right) 

\mathrm{Apply\:minus-plus\:rules} 

\:\:+\left(-a\right)=-a 

2x-2\cdot \:5 

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:5=10 

2x-10 

3x+2x-10=50 

\mathrm{Add\:similar\:elements:}\:3x+2x=5x 

5x-10=50 

\mathrm{Add\:}10\mathrm{\:to\:both\:sides} 

5x-10+10=50+10 

\mathrm{Simplify} 

5x=60 

\mathrm{Divide\:both\:sides\:by\:}5 

\dfrac{5x}{5}=\dfrac{60}{5} 

\mathrm{Simplify} 

x=12 

Hope this helps, 

      AnthrαX <span>  </span>
4 0
3 years ago
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