Idk what is the answers so i see if i got then right
Answer:
Velocity = 59 feet/second
Step-by-step explanation:
h(t) = 15 + 60t – 16t2
Time t = 1 second
Let's substitute time into the equation to get the distance
h(t) = 15+60(1)-16(1)²
h(t) = 15 + 60 - 16
h(t) = 59 feet
Speed or velocity = distance/time
Distance = 59 feet
Time = 1 second
Velocity = 59/1
Velocity = 59 feet/s
Unless you just want to give money to the ice cream truck, for 0 items, you will pay 0.
Since the price of each item is $0.77, for one item you will pay $0.77. (Is that a surprise?)
Then for two items, you will pay $0.77 for each one, or $0.77 + 0.77 = $1.54. You can also compute this by making use of the fact that multiplication is a shortcut for repeated addition. The price can be found by $0.77×2 = $1.54 = f(2).
Similarly, for 3 items, you can add $0.77 three times: $0.77 + 0.77 + 0.77 = f(3), or you can use multiplication: $0.77×3 = $2.31 = f(3).
a) Our table looks like
(x, f(x))
(0, 0)
(1, 0.77)
(2, 1.54)
(3, 2.31)
b) By now, I'm sure you have realized that to find the price of x items, you multiply 0.77 by x.
f(x) = 0.77x
Answer:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:

Step-by-step explanation:
For this case we have the following distribution given:
X 0 1 2 3 4 5 6
P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02
For this case we need to find first the expected value given by:

And replacing we got:

Now we can find the second moment given by:

And replacing we got:

And the variance would be given by:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:

Total fruits→120=4u
apples=30=1u
3u=90→banana and oranges
banana→1u
oranges→2u
oranges=60