If anyone can help it would be greatly appreciated. I will give you 20 extra points for free! Or venmo you $10 :)
2 answers:
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Answer:
25
Step-by-step explanation:
Given that:
Initial payment done for buying the phone = $50
Charges per month for the phone = $25 per month
To find:
The equation to represent the situation and its slope.
Solution:
First of all, let us assume that represents the number of months for which monthly is to be made.
Charges paid for one month = $25
Charges paid for months = $25
Total cost of the phone = Initial payment + Charges paid for months
It is a linear equation between two variables and
.
This equation can be compared with slope intercept form of a line.
Slope intercept form of a line is represented by:
is the slope.
On Comparing, we get:
Therefore, the slope is <em>25</em>.
9514 1404 393
Answer:
see below
Step-by-step explanation:
It is easiest to compare the equations when they are written in the same form.
The first set can be written in slope-intercept form.
y = 2x +7
y = 2x +7 . . . . add 2x
These equations are <em>identical</em>, so have infinitely many solutions.
__
The second set can be written in standard form.
y +4x = -5
y +4x = -10
These equations <em>differ only in their constant</em>, so have no solutions.
__
The third set is already written in slope-intercept form. The equations have <em>different slopes</em>, so have exactly one solution.
Answer:
1) The volume of the frustum is 27·(√3)·h
2) The surface area the frustum is 24·h + 54·√3
Step-by-step explanation:
1) A frustum of the regular triangular prism is a portion of the triangular prism
The length of the edge of the triangle prism = 12
The area of the triangular face, A = (√3/4)·a²
∴ A = (√3/4)·12² = 36·√3
When
The volume of the triangular prism, V = A·h = (36·√3)·h
By triangle proportionality theorem, the cross sectional area of the top half of the triangular prism = (√3/4)·6² = 9·(√3)
The volume of the top half, V₂ = 9·(√3)·h
The volume of the frustum = V - V₂ = (36·√3)·h - 9·(√3)·h = 27·(√3)·h
The volume of the frustum = 27·(√3)·h
2) The surface area of the triangular side of the frustum is given as follows;
A = 36·√3- 9·(√3) = 27·(√3)
The surface area the frustum, = 2×27·(√3) + 2 ×6 ×h + 12×h = 24·h + 54·√3
The surface area the frustum = 24·h + 54·√3