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antoniya [11.8K]
3 years ago
9

How many zero pairs must be added to the function

Mathematics
2 answers:
PtichkaEL [24]3 years ago
4 0

The answer is to the question 3

konstantin123 [22]3 years ago
3 0
TO write the function into vertex form, we need to add one zero and the solution is shown below:
f(x)= x² -6x +1
Add one zero in the form of -9 and 9, such as:
f(x) = x² -6x +1 -9 +9
f(x) = (x² -6x +9) +(1-9)
f(x) = (x-3)² + (-8)
f(x) = (x-3)² - 8
This is the vertex form of the given function and only one zero is being added.
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If 2x2 - 4x + 6 = 1 then A= 2, B = -4, and C = 6 in general form.<br> True<br> False
Leno4ka [110]

Answer:

false

Step-by-step explanation:

6 0
4 years ago
A basketball shot is taken from a horizontal distance of 5m from the hoop. The height of the ball can be modelled by the relatio
olasank [31]
This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation;
h=-7.3t^2+8.25t+2.1+5
The time taken for the ball to hit the ground will be given as falls;
-7.3t^2+8.25t+7.1=0
to solve for t we use the quadratic formula;
t=[-b+/-sqrt(b^2-4ac)]/(2a)
a=-7.3, b=8.25, c=2.1
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or
t=1.702
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7 0
4 years ago
1/5x2/5 how do you multiply fractions? plz show steps
Vladimir79 [104]

Answer: \frac{2}{25} is the solution.

Step-by-step explanation;

Apply the property of fractions. Multiply the numerator with the numerator (1*2) and then the denominator with the denominator (5*5). This will give you: \frac{2}{25}.

7 0
3 years ago
12k^2m^8 / 4km^5 <br><br> How do you do this?
nordsb [41]

9514 1404 393

Answer:

  3km^3

Step-by-step explanation:

The rule of exponents that is useful here is ...

  (a^b)/(a^c) = a^(b-c)

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6 0
3 years ago
A rain gutter is made from sheets of aluminum that are 22 inches wide by turning up the edges to form right angles. Determine th
Varvara68 [4.7K]
So hmm notice the picture below

thus, the perimeter of the gutter is just w + w + l, or 2w +l

thus \bf 22=2w+l\implies 22-2w=l&#10;\\\\\\&#10;\textit{area of a rectangle}\\\\&#10;A=lw\qquad 22-2w=l\implies A(w)=(22-2w)w&#10;\\\\\\&#10;A(w)=22w-2w^2

take the derivative of A(w), zero it out, check any critical points in the interval of (0, 22), for a maxima

recall, the aluminum sheet is just 22inches long, thus, whatever the "depth" or "w" is, has to be more than 0, and less than 22

4 0
3 years ago
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