Answer:
Area of the figure = 200 cm²
Step-by-step explanation:
Area of rectangle A = Length × Width
= 5×9
= 45 cm²
Area of rectangle B = 5 × 11
= 55 cm²
Area of rectangle C = 5 × 9
= 45 cm²
Area of rectangle D = 5 × 7
= 35 cm²
Area of rectangle E = 10 × 2
= 20 cm²
Total area of the figure = 45 + 55 + 45 + 35 + 20
= 200 cm²
This problem is Not Linear
Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
The value of x in the triangle is (a) 22
<h3>How to solve for x?</h3>
The complete question is in the attached image.
From the attached image of the triangle, we have:

Evaluate sin(45)

Solve for x

Divide
x = 22
Hence, the value of x is (a) 22
Read more about special triangles at:
brainly.com/question/654982
#SPJ1
Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90



has a pvalue of 0.9649
X = 82



has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90