3 years ago

Multiply (3p+4q) by (3m+2n).

Mathematics

1 answer:

trapecia [35]3 years ago

5 0

Answer:

9pm + 6pn + 12qm + 8qn

Step-by-step explanation:

Use FOIL (firsts, outers, inners, lasts)

^ this tells you what to multiply

Multiply the firsts 3p × 3m = 9pm

Multiply the outers 3p × 2n = 6pn

Multiply the inners 4q × 3m = 12qm

Multiply the lasts 4q × 2n = 8qn

You might be interested in

Directions: Measure each section of the rocket to the nearest millimeter.

omeli [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

Older people often have a hard time finding work. AARP reported on the number of weeks it takes a worker aged 55 plus to find a

mote1985 [20]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which of the following is true?

Vika [28.1K]

1. |-8| < 6

8 < 6 false

2. |-6| < |-8|

6< 8 true

3. |8| < |-6|

8 < 6 false.

4. |-6| < -8

6 < -8 false

4 0

3 years ago

Find the perimeter of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

choli [55]

Given:

The vertices of a quadrilateral ABCD are A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

To find:

The perimeter of quadrilateral ABCD.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(4-0)^2+(1-4)^2}$

$AB=\sqrt{(4)^2+(-3)^2}$

$AB=\sqrt{16+9}$

$AB=\sqrt{25}$

$AB=5$

Similarly,

$BC=\sqrt{(1-4)^2+(-3-1)^2}$

$BC=5$

$CD=\sqrt{(-3-1)^2+(0-(-3))^2}$

$CD=5$

And,

$AD=\sqrt{(-3-0)^2+(0-4)^2}$

$AD=5$

Now, the perimeter of the quadrilateral ABCD is:

$P=AB+BC+CD+AD$

$P=5+5+5+5$

$P=20$

Therefore, the perimeter of the quadrilateral ABCD is 20 units.

6 0

3 years ago

Please help me, ASAP!

mr_godi [17]

6*10 =$60 for sugar sticks
14*8=$112 for jelly beans

Thus, $60 + $112 = $172 for overall candy mixture.

7 0

3 years ago

Multiply (3p+4q) by (3m+2n).​

Multiply (3p+4q) by (3m+2n).