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NNADVOKAT [17]
3 years ago
8

Multiply (3p+4q) by (3m+2n).​

Mathematics
1 answer:
trapecia [35]3 years ago
5 0

Answer:

9pm + 6pn + 12qm + 8qn

Step-by-step explanation:

Use FOIL (firsts, outers, inners, lasts)

^ this tells you what to multiply

Multiply the firsts 3p × 3m = 9pm

Multiply the outers 3p × 2n = 6pn

Multiply the inners 4q × 3m = 12qm

Multiply the lasts 4q × 2n = 8qn

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Don't know how to solve please help
lesantik [10]

50+ <DGE+2X=180

<DGE+2X=130

2X=100

X=50

4 0
3 years ago
Read 2 more answers
9x - 3y = -2<br> -3x + y = -3
morpeh [17]
Multiply 2nd equation by 3 and add to first
9x-3y=-2
<u>-9x+3y=-9 +</u>
0x+0y=-7

0=-7
false
no solution
these lines aer paraalell so no solution
6 0
3 years ago
17.
777dan777 [17]

Answer:

$12.5

Step-by-step explanation:

Since prize is split equally.

So, money received by each person

= 75/6

= $12.5

7 0
3 years ago
Which graph represents the solution set of the system of inequalities? {x+y&lt;12 y≥x−4
RSB [31]

Answer: The graph in the bottom right-hand corner

(see figure 4 in the attached images below)

===========================================

Explanation:

Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.

Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.

After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.

5 0
3 years ago
Read 2 more answers
Which equation would you use to solve this problem?
const2013 [10]
I have no idea what is is but try 4 or 1,If not you should go on cymath
8 0
3 years ago
Read 2 more answers
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