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Law Incorporation [45]
3 years ago
6

An office building has two elevators. One elevator starts out on the 4th floor, 35 feet above the ground, as it’s defending at a

rate of 2.2 feet per second. The other elevator starts out at ground level and is rising at a rate of 1.7 feet per second. Write a system of equations to represent the situation
Mathematics
1 answer:
iren2701 [21]3 years ago
6 0

The system of equations are y = 35 - 2.2x and y = 1.7x

<em><u>Solution:</u></em>

Given that, office building has two elevators.

<em><u>One elevator starts out on the 4th floor, 35 feet above the ground, as it’s descending at a rate of 2.2 feet per second</u></em>

Let "x" be the number of seconds for which the elevator is descending

Therefore, for "x" seconds the descended feet is 2.2x feet

The elevator is at 4 th floor, 35 feet above ground

Therefore, from 35 feet, the elevator has descended 2.2x feet for "x" seconds

Let "y" be the final position of elevator after "x" seconds

Therefore,

y = 35 - 2.2x

<em><u>The other elevator starts out at ground level and is rising at a rate of 1.7 feet per second</u></em>

Here, the elevator is rising at a rate of 1.7 feet per second

Therefore, for "x" seconds, the elevator has raised 1.7x feet

Here the elevator is at ground level, therefore

y = 1.7x

Thus the system of equations are y = 35 - 2.2x and y = 1.7x

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