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e-lub [12.9K]
3 years ago
6

Although a star might look brighter than the Sun, a comparison of its ______________ magnitude might help prove that they have t

he same real brightness.
Biology
2 answers:
amid [387]3 years ago
7 0
<span>Although a star might look brighter than the Sun, a comparison of its absolute<span> magnitude might help prove that they have the same real brightness.
Absolute magnitude is a concept that compares the absolute brightness of celestial objects. The absolute magnitude of an object is defined as the apparent magnitude it would have if it were viewed at a standard distance of 10 parsecs (32.6 light-years) with no dimming of its light. The more luminous an object, the smaller the numerical value of its absolute magnitude.</span></span>
STatiana [176]3 years ago
4 0

Answer:

Although a star might look brighter than the Sun, a comparison of its <u>Absolute </u>magnitude might help prove that they have the same real brightness.  

Explanation:

Apparent magnitude measures the brightness of a celestial body from the Earth at its actual position.

Absolute magnitude is the apparent magnitude of the same body when it is at a distance of 10 parsecs.

A star might look brighter than the sun but actual comparison of the brightness can be done by comparing the absolute magnitudes of the two stars.

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HELP ASAP I WILL GIVE BRAINLIST
adelina 88 [10]

Answer:

1) CO₂

2) 0.2551 g

Explanation:

The balanced reactions are:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂

1) The gas produced is CO₂.

2) Calculate mass of CaCO₃:

(0.5236 g) (0.4230) = 0.2215 g CaCO₃

Convert to moles:

(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃

Find moles of CaCO₃:

(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂

Convert to mass:

(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂

Calculate mass of MgCO₃:

(0.5236 g) (0.5770) = 0.3021 g MgCO₃

Convert to moles:

(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃

Find moles of MgCO₃:

(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂

Convert to mass:

(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂

Total mass of CO₂:

0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂

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3 years ago
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lilavasa [31]

Answer:

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Explanation:

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