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Tema [17]
3 years ago
8

Guys, my teachers keeps giving me C's for assignments im doing right! Can I switch teachers its only the 3rd week of school..?

Mathematics
1 answer:
Kaylis [27]3 years ago
3 0
I think you would have to talk to your advisor
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Several paint mixtures are made by mixing blue paint and white paint. Paint Colors Blue Paint White Paint Mixture A 5 cups 12 cu
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c is right

Step-by-step explanation:

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Write an equation of the line in slope-intercept form given the graph below.
Elza [17]

Answer:

y=-1/3x-1

Step-by-step explanation:

1. Find the slope.

Start from the point on the y-axis and count down and over until you get to the other point marked on the graph. This gets you -1/3

Slope is -1/3

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3. Put the equation in slope-intercept form. Slope intercept form is y=mx+b with mx being the slope and b being the y-intercept.

y=-1/3x-1

4 0
3 years ago
Which numbers I have to put in the boxes
djyliett [7]
Where’s the problem
5 0
1 year ago
Write a number or expression in each empty box to create true equations.
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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\


\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
\\\\\\
\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
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