Answer:
y = -3/4x + 3
Step-by-step explanation:
y - 9 = -3/4 (x-8)
y-9 = -3/4x -6
y = -3/4x - 6 + 9
y = -3/4x + 3
Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
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We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
![\left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C1%2B2%261-3%261-1%261000%2829%2B1%29%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C3%26-2%260%2630000%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D)
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
1st gift shop:
120/4 = 30 cents each
180/6 = 30 cents each
390/13 = 30 cents each
2nd gift shop:
204/7 = 29.14 cents each
192/8 = 24 cents each
270 /9 = 30 cents each
360/10 = 36 cents each
so if both gift shops have a fixed price then the 9 post cards would be the answer since it matches 30 each like the 1st gift store
Answer: Table H would be the correct answer;
The rule of a function is that for each x-value given there can't be more than 1 y-value
<u>In Table F:</u>
x = -13, then y = -2
x = -13, then y = 0
x = -13, then y = 5
x = -13, then y = 7
For the x-value -13, there are 4 different y-values, so <em>it's not a function.</em>
<u>In Table G:</u>
x = -6, then y = 3
x = -1, then y = -1
x = -1, then y = 5
x = 10, then y = -9
For the x-value -1, there are 2 different y-values, hence <em>this isn't a function.</em>
<u>In Table H:</u>
x = 1, then y = 4
x = 3, then y = 4
x = 7, then y = 4
x = 12, then y = 4
For each x-value, there is only 1 y-value, so <em>this is a function.</em>
<u>In table J:</u>
x = -9, then y = -7
x = -2, then y = -5
x = 0, then y = 0
x = 0, then y = 6
For the x-value 0, there are 2 different y-value therefore <em>this isn't a function</em>
Hope this helps!
Answer:
97.3%
Step-by-step explanation:
Let the three bulbs be A, B and C respectively.
Let P(A) denote the probability that the first bulb will burn out
Let P(B) denote the probability that the second bulb will burn out
Let P(C) denote the probability that the third bulb will burn out
Now, we are told that Each one has a 30% probability of burning out within the month.
Thus;
P(A) = P(B) = P(C) = 30% = 0.3
Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;
P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))
P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%
