Answer: B
Step-by-step explanation: I feel like it's b but it is too easy
We know that
g=3
r=2
b=5
total marbies=g+r+b------> 3+2+5----> 10
a) <span>probability that the first marble is red
P(red)=r/total marbies------------> 2/10-----> 1/5
b) </span><span>probability that the second marble is blue
in this case total marbles-------> 9
P(blue)=b/total marbles----------> 5/9
c) </span><span>the probability that the first marble is red and the second is blue
(1/5)*(5/9)=1/9
the answer is
1/9</span>
1+tan^2(y)=1/cos^2(y)
cos 2y -1=cos^2(y) -sin^2(y)-cos^2(y) -sin^2(y)
Each face of the cube has an equal probability of being rolled. There are 2 numbers on the cube less than 3 (1 and 2). The event of rolling a 1 and the event of rolling a 2 are mutually exclusive (you can't roll both faces at once), so
Answer:
12a + .5B
B= -6a
a=.042B
Step-by-step explanation:
1/2(6a+B)= 12a+.5B
1/2(6a+B)=0
-12a=.5B
-6a=B
12a=-.5B
a=.042B