Step 1: Make equation equal to Zero
3x^2 = 4x + 2
3x^2 - 4x - 2
Step 2: use equation
a= 3 b = -4 c= -2
after plugging in answer should be
(2 + or - sqrt 10) / 3
Answer:
The Length of <em>JK</em> is 10
Step-by-step explanation:
Because <<em>J </em>is congruent to <<em>L</em> we know that the triangle in question must be isosceles as in an isosceles triangle two angles opposite of each other are equal. (This is also true for equilateral triangles, however, in an equilateral triangle all sides must be congruent, so we can rule equilateral out as <em>LJ </em>is not congruent to <em>KL.) </em>This means that the triangle must be isosceles.
In an isosceles triangle the side opposite each other are congruent, and the angles opposite each other are congruent when split down the line of symmetry.
Therefor, the length of <em>JK </em>must be congruent to the length of <em>KL. </em>In other words if <em>JK </em>= 10, then <em>KL </em>must equal 10 as well.
Answer:
- h(x) = -2x^2 -x +3
- Reservoir A releases the same amount of water as Reservoir B over 1 week
Step-by-step explanation:
<u>Given</u>:
f(x) = x^2 -7x +5
g(x) = 3x^2 -6x +2
h(x) = f(x) -g(x)
<u>Find</u>:
h(x)
h(1)
<u>Solution</u>:
The expression for h(x) is found by evaluating its definition:
h(x) = (x^2 -7x +5) -(3x^2 -6x +2)
h(x) = x^2(1 -3) +x(-7 -(-6)) +(5 -2)
h(x) = -2x^2 -x +3
Then h(1) is found by substituting 1 for x:
h(1) = -2(1^2) -(1) +3 = -2 -1 +3
h(1) = 0 . . . . difference in release amounts after 1 week is 0
The true statements are ...
- h(x) = -2x^2 -x +3
- Reservoir A releases the same amount of water as Reservoir B over 1 week
Answer:
1. 75 feet
2. 27 seconds
Step-by-step explanation:
1. If six seconds is equal to 10 feet that means that 42 seconds is equal to 70 feet (6 X 7 = 42) It also means that 3 seconds is equal to 5 feet. (42 + 3 = 45)
2. If 6 seconds is 10 feet, then 6 X 4 is 40 feet (24) And since 5 feet is equal to 3 seconds then we get 24 + 3 = 27
Answer:
Step-by-step explanation:
<u>Solving</u> :
⇒ log y = log (x²)
⇒ log y = 2 log x
⇒ 
⇒ 
