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Bad White [126]
3 years ago
11

How would you describe a linear learning curve. Choose the best available answer. for each unit of time the performance improves

a proportional amount for each unit of time the performance decreases a proportional amount the performer displays rapid initial improvement followed by a decline in the rate of improvement the performer displays little initial improvement followed a rapid increase in the rate of improvement none of the above
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

My answer would be; the performer displays rapid initial improvement followed by a decline in the rate of improvement.

Step-by-step explanation:

Usually a learning curve means that struggles are occurring after time of understanding and if we were creating a linear graph of this learning curve, it would be decreasing.

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i think 2.7

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if not have a great life

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What is 1.532 rounded to the nearest hundredth
Anni [7]

Answer:

1.53 would be the answer

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If you are rounding to the nearest hundredth you are rounding to the 2nd decimal place. Since the next number is under 5, we would just drop it.

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Simplify the following by removing parentheses and combining terms<br> -(2q+6)+3(2q+4)-2q
Gelneren [198K]

Answer:

2q+6

Step-by-step explanation:

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-2q-6+6q+12-2q

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Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!​
Misha Larkins [42]

Answer:

[0.25, 2]

Step-by-step explanation:

We have

4t² ≤ 9t-2

subtract 9t-2 from both sides to make this a quadratic

4t²-9t+2 ≤ 0

To solve this, we can solve for 4t²-9t+2=0 and do some guess and check to find which values result in the function being less than 0.

4t²-9t+2=0

We can see that -8 and -1 add up to -9, the coefficient of t, and 4 (the coefficient of t²) and 2 multiply to 8, which is also equal to -8 * -1. Therefore, we can write this as

4t²-8t-t+2=0

4t(t-2)-1(t-2)=0

(4t-1)(t-2)=0

Our zeros are thus t=2 and t = 1/4. Using these zeros, we can set up three zones: t < 1/4, 1/4<t<2, and t>2. We can take one random value from each of these zones and see if it fits the criteria of

4t²-9t+2 ≤ 0

For t<1/4, we can plug in 0. 4(0)²-9(0) + 2 = 2 >0 , so this is not correct

For 1/4<t<2, we can plug 1 in. 4(1)²-9(1) +2 = -3 <0, so this is correct

For t > 2, we can plug 5 in. 4(5)²-9(5) + 2 = 57 > 0, so this is not correct.

Therefore, for 4t^2 ≤ 9t-2 , which can also be written as 4t²-9t+2 ≤ 0, when t is between 1/4 and 2, the inequality is correct. Furthermore, as the sides are equal when t= 1/4 and t=2, this can be written as [0.25, 2]

8 0
3 years ago
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