- The parabola opens upward
- The x-intercepts at (-4, 0) and (1, 0)
- The y-intercept is the point (0, -4)
- The axis of symmetry is x = - ³/₂
- The minimum value is -6¹/₄
- The vertex is (- ³/₂, - 6¹/₄)
The quadratic function is described by the standard equation
We have the quadratic function
Let us configure it to obtain a standard equation.
Hence, we get
- We identify the coefficients a, b, and c. For this equation,
- The parabola opens upward because a > 0, resulting in a vertex that is a minimum.
- The y-intercept of the quadratic function f(x) = x² + 3x - 4 is (0, c), i.e., the point
- From
we get the x-intercepts at
- The axis of symmetry is
, i.e.,
- The minimum value is
- The vertex is
where
or
Finding the minimum value is as follows:
<u>Notes:</u>
- The graph of a quadratic function is called a parabola.
- When a > 0, the parabola opens upward, resulting in a vertex that is a minimum.
- When a < 0, the parabola opens downward, resulting in a vertex that is a maximum.
- The value c is the y-intercept of the graph, because a y-intercept is a point on the graph where x is zero. In other words, the graph passes through the point
- From
we get x-intercepts at
- An x-intercept represents a point on the graph where y is zero.
- The axis of symmetry represent the line that passes through the vertex of parabola with equation
- The vertex is
- A line that is not parallel to either the x-axis or the y-axis brainly.com/question/4691222
- Finding the y-intercept of the quadratic function f(x) = (x – 6)(x – 2) brainly.com/question/1332667
- The midpoint brainly.com/question/3269852
Keywords: which is the graph of f(x) = (x - 1)(x + 4), the x-intercept, quadratic function, a standard equation, the y-intercept, the axis of symmetry, the vertex, parabola, upward, downward
