Factorize: a^2+10ab -75b^2
2 answers:
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The sum of three consecutive integers is three times the middle one: if we call the middle one , the three numbers are
So, their sum is
Which is three times the middle one.
So, if the sum of three consecutive intergers is 48, the middle one must be 48/3 = 16.
So, the three numbers are 15, 16 and 17
Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.