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Kipish [7]
3 years ago
6

Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t

he first term.
6, 7, 8, 9, ...
Mathematics
1 answer:
inessss [21]3 years ago
5 0

Step-by-step explanation:

a_1=6\\a_2=a_1+1\to a_2=6+1=7\\a_3=a_2+1\to a_3=7+1=8\\a_4=a_3+1\to a_4=8+1=9\\\vdots\\\\\text{The recursive formula}\\a_n=\left\{\begin{array}{ccc}a_1=6\\a_n=a_{n-1}+1\end{array}\right\\\\\text{It's an arithmetic sequence with}\ a_1=6\ \text{and difference}\ d=1\\\\\text{The explicit formula of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\\text{Substitute:}\\\\a_n=6+(n-1)(1)\\a_n=6+n-1\\a_n=5+n\\\\a_n=n+5

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Need Help Please with q2 & q4!!
nasty-shy [4]

Answer:

t(x) = 6x + 438

Step-by-step explanation:

I dont know question 4 but if you copy and paste question 2 it is already answered on this site, hope this helps!

7 0
3 years ago
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PLEASE ANSWER THIS AS SOON AS POSSIBLE AND CORRECTLY
skad [1K]

Answer:

Y-Intercept would be 2, Slope would be 1

Step-by-step explanation:

6 0
3 years ago
Motion and rate of change derivatives. Attached is the question and where I am stuck, I would really appreciate the help :)
barxatty [35]

Answer:

A. 3 < t < 9

Step-by-step explanation:

When the particle is moving to the right, the velocity is positive.

To find the velocity, take the derivative of s(t) with respect to t.

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4 0
4 years ago
If a parabola had a y-intercept of (0,5) and an axis of symmetry at x = 4, what other point must be on the graph? (hint: draw)
Serga [27]

Answer:

(8, 5)

Step-by-step explanation:

Let's take a look at the y-intercept, (0, 5).  If the axis of symmetry is x = 4, then the distance from (0, 5) is 4 units.  If we reflect this point (0, 5) about the axis of symmetry x = 4, the resulting point is (8, 5).  In other words, the distance from the y-intercept to the axis of symmetry is 4 units, and so the distance from the y-intercept must be 4 units plus 4 units, or 8 units.

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3 0
3 years ago
the model represents the factorization of 2x2+5x+3. what are the factors of the polynomial.(2x+3)(x+1),(2x-3)(x-1),(3x+2)(x-1),(
Maurinko [17]

Answer:

The factors of the polynomial are (2x + 3)(x + 1) ⇒ 1st answer

Step-by-step explanation:

* Lets explain how to factor a trinomial in the form ax² ± bx ± c  

- Look at the c term first.  

# If the c term is a positive number, then its factors r , s will both  

  be positive or both be negative it depends on the sign of b, if b  

  positive then both are positive if b negative then both are negative  

# a has two factors h and k  

# The brackets are (hx ± r)(kx ± s) where a = hk , c = rs and b = rk + hs  

# If the c term is a negative number, then either r or s will be negative,  

  but not both.  

# a has two factors h and k  

# The brackets are (hx + r)(kx - s) where a = hk , c = rs and b = rk - hs  

* Lets solve the problem

∵ The trinomial is 2x² + 5x + 3

∴ a = 2 , b = 5 , c = 3

∵ c is positive

∴ Its factors r and s have same sign

∵ b is positive

∴ r and s both positive

∵ a = 2  

∵ The factors of a are h , k

∵ 2 = 2 × 1

∴ h = 2 and k = 1

∵ c = 3

∵ The factors of c are r , s

∵ 3 = 3 × 1

∴ r = 3 and s = 1

∵ The brackets are (hx + r)(kx + s)

∴ 2x² + 5x + = (2x + 3)(x + 1)

* The factors of the polynomial are (2x + 3)(x + 1)

7 0
3 years ago
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