Answer: C 2.5%
Step-by-step explanation:
The "Rule of 72" is a easy way to calculate how much time an investment will take to double with a given fixed annual rate of interest.
Just we have to divide 72 by the annual rate of return(r), we can get a rough estimate of how many years it will take to double the initial investment .
Now, in given problem: Let 'r' be the rate of interest
Time to double the amount=29 years
Thus by rule 72 ,
![\frac{72}{r}=29\\\Rightarrow\ r=\frac{72}{29}=2.4827\%\approx2.5\%](https://tex.z-dn.net/?f=%5Cfrac%7B72%7D%7Br%7D%3D29%5C%5C%5CRightarrow%5C%20r%3D%5Cfrac%7B72%7D%7B29%7D%3D2.4827%5C%25%5Capprox2.5%5C%25)
Therefore, C is the right option.
Answer:
Equation to represent the situation = ![800=Y(1.05)^X](https://tex.z-dn.net/?f=800%3DY%281.05%29%5EX)
Step-by-step explanation:
Given:
Initial investment = Y
Growth rate (r) = 5% = 5 / 100 = 0.05
Number of year (n) = X year
Amount after X year = $800
Find:
Equation to represent the situation:
Computation:
![Amount = Initial\ investment (1+r)^n\\\\800 = Y (1+0.05)^X\\\\800 = Y (1.05)^X\\\\](https://tex.z-dn.net/?f=Amount%20%3D%20Initial%5C%20investment%20%281%2Br%29%5En%5C%5C%5C%5C800%20%3D%20Y%20%281%2B0.05%29%5EX%5C%5C%5C%5C800%20%3D%20Y%20%281.05%29%5EX%5C%5C%5C%5C)
Equation to represent the situation = ![800=Y(1.05)^X](https://tex.z-dn.net/?f=800%3DY%281.05%29%5EX)
99 and 59
X=big number
X-40 = small
X+ x-40 =158
2X -40=158
2X =198
X=99. Big number is 99
99-40 =59
99+59=158
Answer:
b. the area to the right of 2
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.
In this problem:
![X = 96, \mu = 72, \sigma = 12](https://tex.z-dn.net/?f=X%20%3D%2096%2C%20%5Cmu%20%3D%2072%2C%20%5Csigma%20%3D%2012)
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{96 - 72}{12}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B96%20-%2072%7D%7B12%7D)
![Z = 2](https://tex.z-dn.net/?f=Z%20%3D%202)
Percentage who did better:
P(Z > 2), which is the area to the right of 2.
Answer:
6 pints
Step-by-step explanation:
There are two pints in a quart, so there are 2 times 3 pints in three quarts.
Hope this helps!