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Softa [21]
3 years ago
9

Can someone help me find the value of x and the value of y? I need them to show their work, too.

Mathematics
1 answer:
solniwko [45]3 years ago
4 0

\bf \begin{cases} x-2y=0\\ 2x-5y=-4 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ x-2y=0\implies x=2y \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting the found \underline{x} in the 2nd equation}}{2(2y)-5y=-4}\implies 4y-5y=-4\implies -y=-4 \\\\\\ y=\cfrac{-4}{-1}\implies \blacktriangleright y=4 \blacktriangleleft \\\\[-0.35em] ~\dotfill

\stackrel{\textit{substituting the found \underline{y} in the 1st equation}}{x-2(4)=0}\implies x-8=0\implies \blacktriangleright x=8 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (8,4)~\hfill

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disa [49]

Answer:

y = \frac{5x-11}{8}

Step-by-step explanation:

Given

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- 8y = 11 - 5x ( multiply through by - 1 )

8y = - 11 + 5x = 5x - 11 ( divide both sides by 8 )

y = \frac{5x-11}{8}

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3 years ago
Add.<br> (-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)<br> express the answer in standard form.
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3 years ago
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Step-by-step explanation:x_{3}

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move the constant to the right

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divide both sides

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