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Lorico [155]
3 years ago
10

The time required for a citizen to complete the 2010 U.S. Census ""long"" form is normally distributed with a mean of 40 minutes

and a standard deviation of 10 minutes. What is the third quartile (in minutes) for the time required to complete the form?
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

46.75 minutes

Step-by-step explanation:

Mean time (μ) = 40 minutes

Standard deviation (σ) = 10 minutes

The third quartile is at the 75th percentile of a normal distribution. According to a z-score table, the corresponding z-score for the 75th percentile is z=0.675.

The z-score for any given time, 'X', is:

z=\frac{X- \mu}{\sigma}

The third quartile for the time required to complete the form is:

0.675=\frac{X- 40}{10}\\X= 40+6.75=46.75\ minutes

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Answer:

  y = (1/3)x^3 +4x + c . . . . . for some constant c

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The anti-derivative of x^n is (x^(n+1))/(n+1). Applying this rule to each of the terms in dy/dx, we get ...

  y = (1/3)x^3 + 4x

There may be an added constant as well, conventionally represented by "c".

  y = (1/3)x^3 +4x +c

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4 years ago
choose yes or no to indicate which of the equations can be used to describe the pattern in the table (am i correct??????)​
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Step-by-step explanation:

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3 years ago
Bob has 4,000 grams of sand. If his brother has one kilogram more than Bob, how many kilograms of sand does Bob's brother have?
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6 0
3 years ago
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2[2y-1]+5=19 what are the solutions?
skelet666 [1.2K]

Answer:

y = 4

Step-by-step explanation:

2[2y-1]+5=19   (by PEDMAS, distribute parentheses first)

(2)(2y) - (2)(1) + 5 = 19

4y - 2 + 5 = 19

4y +3 = 19    (subtract 3 from both sides)

4y = 19 - 3

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5 0
3 years ago
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Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

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  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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