Hola!
A rational number could range from 10.21 to 10.2001
Hope that helped :)
Answer:
A. No, this is not a valid inference because he asked only 20 families
Step-by-step explanation:
You cannot assume that those are the only families that would want to go; you have to ask all the families.
Number of books each of them have:
Jaime: x
Grant: x - 6
Ky: 3 (x - 6)
There are 176 books in total, so we can write it down as:
176 = x + x - 6 + 3 (x - 6)
176 = x + x - 6 + 3 * x + 3 * (-6)
176 = x + x - 6 + 3x - 18
176 = 2x - 6 + 3x - 18
176 = 5x - 24 / + 24 (both sides)
5x = 200 / ÷ 5 (both sides)
x = 40
Doublecheck:
Jamie: 40
Grant: 40 - 6 = 34
Ky: 3 (40 - 6) = 3 * 34 = 102
102 + 34 + 40 = 176, so it's correct :)
Answer:
15187.5=2000(1.5)^5
Step-by-step explanation:
So right now he has 2000 in his saving each year it grows by 1.5 so by year 5 it should be
15187.5 in his savings
hope I did it right
Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
