I thought I saw this one earlier and there were people answering. Guess not.
h(t) = 5 + 98t - 4.9t²
h(0) = 5 meters
h(5) = 5 + 98(5) - 4.9(5)² = 372.5 meters
h(10) = 5 + 98(10) - 4.9(10)² = 5 + 980 - 490 = 495 meters
h(15) = 5 + 98(15) - 4.9(15²) = 372.5 meters
h(20) = 5 meters
I'll leave the graphing to you, plot those points
(0,5), (5,372,5),(10,495),(15,372.5) (20,5)
and connect the dots
It's coming down pretty fast at 5 feet up 20 seconds. That last bit is 5/495 or 1% of the trip, so probably double the average speed of around 50m/s so 100msec or .05 sec to go 5 meters.
So it's in the ground at about 20.05 seconds after launch.
Answer: 20.05 meters
Answer:
The total length of border was
Step-by-step explanation:
we know that
The length of the border would be the circumference of the circle,
The circumference of the circle is equal to
In this problem we have
-----> given problem
substitute
assume
to get the slope, all we need is two points, so let's pick two off the table.
Answer:
$.53 per ball
Step-by-step explanation:
The total cost of the golf balls is $9.54
There were 18 golf balls
The cost per golf ball is cost/ number of balls
9.54/18
.53
$.53 per ball
Step-by-step explanation:
In ΔKLM, l = 570 cm, k = 490 cm and ∠K=46°. Find all possible values of ∠L, to the nearest degree.
K
L
M
k = 490
l = 570
46°
?°
\frac{\sin A}{a}=\frac{\sin B}{b}
a
sinA
=
b
sinB
From the reference sheet (reciprocal version).
\frac{\sin L}{570}=\frac{\sin 46}{490}
570
sinL
=
490
sin46
Plug in values.
\sin L=\frac{570\sin 46}{490}\approx 0.836783
sinL=
490
570sin46
≈0.836783
Evaluate.
L=\sin^{-1}(0.836783)\approx 56.8\approx 57^{\circ}
L=sin
−1
(0.836783)≈56.8≈57
∘
Inverse sine and round.
\text{Quadrant II: } 180-57=123^{\circ}
Quadrant II: 180−57=123
∘
Sine is positive in quadrants 1 and 2.
\text{Check for possibility:}
Check for possibility:
No triangle's angles may add to more than 180.
46+57=103
46+57=103
∘
←Possible
Less than 180.
46+123=169}
46+123=169
∘
←Possible
Less than 180.
Answer: 57
and 123