Area of square/rectangle = length times width
Answer:



The standard deviation will remain unchanged.
Step-by-step explanation:
Given

Solving (a): The range
This is calculated as:

Where:

So:


Solving (b): The variance
First, we calculate the mean




The variance is calculated as:

So, we have:
![\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B6-1%7D%2A%5B%28136%20-%20135%29%5E2%20%2B%28129%20-%20135%29%5E2%20%2B%28141%20-%20135%29%5E2%20%2B%28139%20-%20135%29%5E2%20%2B%28138%20-%20135%29%5E2%20%2B%28127%20-%20135%29%5E2%5D)
![\sigma^2 =\frac{1}{5}*[162]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B5%7D%2A%5B162%5D)

Solving (c): The standard deviation
This is calculated as:


--- approximately
Solving (d): With the stated condition, the standard deviation will remain unchanged.
D would be the best option in my opinion
I think that the best visual representation that the marine biologist would use is utilising a bar graph. A bar graph is composed of bars residing in a coordinate plane. In addition to that, the visual representation would most likely be used since the average weight and length of each trout coming from 5 different locations is compared.
Do you still need the answer to this or nah??