What is 6(2y+8)-2(3y-2)

2 answers:

7 0

First, distribute.

6 • 2y = 12y

6 • 8 = 48

this would equal

12y + 48

then do the same for the other part

2 • 3y = 6y

2 • 2 = 4

this would equal

6y + 4

put them all into one.

12y + 48 - 6y + 4

combine the like terms..

12y - 6y = 6y

48 + 4 = 52

the final answer would be 6y + 52

lisov135 [29]4 years ago

6 0

The answer is 6y + 52.

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In triangle ABC m A.47 B.109 C.114 D.71

sashaice [31]

Answer:

Step-by-step explanation:

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3 years ago

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$