I need more to answer that can you maybe zoom out
Answer:
Q (2.5, -4)
Step-by-step explanation:
Let A (1, -5), C = (10, 1), find Q (x, y), so that AQ:QC = 1:5
AQ = (x - 1, y + 5)
QC = (10 - x, 1 - y)
AQ:QC = 1:5
so 5*AQ = QC
5(x - 1) = (10 - x)
5(y + 5) = 1 - y
Solve them:
5x - 5 = 10 - x
6x = 15
x = 15/6 = 2.5
5y + 25 = 1 - y
6y = -24
y = -24/6 = -4
Then answer is Q (2.5, -4)
It = 6.888888888 and you can round it to 7
The engine would need three gallons of gas.
12/4=3
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
